3.4.60 \(\int \frac {x^8 (a+b x^3)^{2/3}}{a d-b d x^3} \, dx\)

Optimal. Leaf size=177 \[ \frac {a^{8/3} \log \left (a-b x^3\right )}{3 \sqrt [3]{2} b^3 d}-\frac {a^{8/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} b^3 d}-\frac {2^{2/3} a^{8/3} \tan ^{-1}\left (\frac {2^{2/3} \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} b^3 d}-\frac {a^2 \left (a+b x^3\right )^{2/3}}{2 b^3 d}-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d} \]

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Rubi [A]  time = 0.20, antiderivative size = 177, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {446, 88, 50, 55, 617, 204, 31} \begin {gather*} -\frac {a^2 \left (a+b x^3\right )^{2/3}}{2 b^3 d}+\frac {a^{8/3} \log \left (a-b x^3\right )}{3 \sqrt [3]{2} b^3 d}-\frac {a^{8/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} b^3 d}-\frac {2^{2/3} a^{8/3} \tan ^{-1}\left (\frac {2^{2/3} \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} b^3 d}-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^8*(a + b*x^3)^(2/3))/(a*d - b*d*x^3),x]

[Out]

-(a^2*(a + b*x^3)^(2/3))/(2*b^3*d) - (a + b*x^3)^(8/3)/(8*b^3*d) - (2^(2/3)*a^(8/3)*ArcTan[(a^(1/3) + 2^(2/3)*
(a + b*x^3)^(1/3))/(Sqrt[3]*a^(1/3))])/(Sqrt[3]*b^3*d) + (a^(8/3)*Log[a - b*x^3])/(3*2^(1/3)*b^3*d) - (a^(8/3)
*Log[2^(1/3)*a^(1/3) - (a + b*x^3)^(1/3)])/(2^(1/3)*b^3*d)

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 55

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(1/3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/b, 3]}, -Simp[L
og[RemoveContent[a + b*x, x]]/(2*b*q), x] + (Dist[3/(2*b), Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x)^(1/
3)], x] - Dist[3/(2*b*q), Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x] && PosQ
[(b*c - a*d)/b]

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {x^8 \left (a+b x^3\right )^{2/3}}{a d-b d x^3} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {x^2 (a+b x)^{2/3}}{a d-b d x} \, dx,x,x^3\right )\\ &=\frac {1}{3} \operatorname {Subst}\left (\int \left (-\frac {(a+b x)^{5/3}}{b^2 d}+\frac {a^2 (a+b x)^{2/3}}{b^2 (a d-b d x)}\right ) \, dx,x,x^3\right )\\ &=-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d}+\frac {a^2 \operatorname {Subst}\left (\int \frac {(a+b x)^{2/3}}{a d-b d x} \, dx,x,x^3\right )}{3 b^2}\\ &=-\frac {a^2 \left (a+b x^3\right )^{2/3}}{2 b^3 d}-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d}+\frac {\left (2 a^3\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{a+b x} (a d-b d x)} \, dx,x,x^3\right )}{3 b^2}\\ &=-\frac {a^2 \left (a+b x^3\right )^{2/3}}{2 b^3 d}-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d}+\frac {a^{8/3} \log \left (a-b x^3\right )}{3 \sqrt [3]{2} b^3 d}+\frac {a^{8/3} \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{2} \sqrt [3]{a}-x} \, dx,x,\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} b^3 d}-\frac {a^3 \operatorname {Subst}\left (\int \frac {1}{2^{2/3} a^{2/3}+\sqrt [3]{2} \sqrt [3]{a} x+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )}{b^3 d}\\ &=-\frac {a^2 \left (a+b x^3\right )^{2/3}}{2 b^3 d}-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d}+\frac {a^{8/3} \log \left (a-b x^3\right )}{3 \sqrt [3]{2} b^3 d}-\frac {a^{8/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} b^3 d}+\frac {\left (2^{2/3} a^{8/3}\right ) \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}\right )}{b^3 d}\\ &=-\frac {a^2 \left (a+b x^3\right )^{2/3}}{2 b^3 d}-\frac {\left (a+b x^3\right )^{8/3}}{8 b^3 d}-\frac {2^{2/3} a^{8/3} \tan ^{-1}\left (\frac {1+\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt {3} b^3 d}+\frac {a^{8/3} \log \left (a-b x^3\right )}{3 \sqrt [3]{2} b^3 d}-\frac {a^{8/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} b^3 d}\\ \end {align*}

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Mathematica [A]  time = 0.17, size = 153, normalized size = 0.86 \begin {gather*} \frac {4\ 2^{2/3} a^{8/3} \log \left (a-b x^3\right )-8\ 2^{2/3} \sqrt {3} a^{8/3} \tan ^{-1}\left (\frac {\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}+1}{\sqrt {3}}\right )-3 \left (4\ 2^{2/3} a^{8/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )+\left (a+b x^3\right )^{2/3} \left (5 a^2+2 a b x^3+b^2 x^6\right )\right )}{24 b^3 d} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^8*(a + b*x^3)^(2/3))/(a*d - b*d*x^3),x]

[Out]

(-8*2^(2/3)*Sqrt[3]*a^(8/3)*ArcTan[(1 + (2^(2/3)*(a + b*x^3)^(1/3))/a^(1/3))/Sqrt[3]] + 4*2^(2/3)*a^(8/3)*Log[
a - b*x^3] - 3*((a + b*x^3)^(2/3)*(5*a^2 + 2*a*b*x^3 + b^2*x^6) + 4*2^(2/3)*a^(8/3)*Log[2^(1/3)*a^(1/3) - (a +
b*x^3)^(1/3)]))/(24*b^3*d)

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IntegrateAlgebraic [A]  time = 0.22, size = 214, normalized size = 1.21 \begin {gather*} -\frac {2^{2/3} a^{8/3} \log \left (2^{2/3} \sqrt [3]{a+b x^3}-2 \sqrt [3]{a}\right )}{3 b^3 d}+\frac {a^{8/3} \log \left (2 a^{2/3}+2^{2/3} \sqrt [3]{a} \sqrt [3]{a+b x^3}+\sqrt [3]{2} \left (a+b x^3\right )^{2/3}\right )}{3 \sqrt [3]{2} b^3 d}-\frac {2^{2/3} a^{8/3} \tan ^{-1}\left (\frac {2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt {3} \sqrt [3]{a}}+\frac {1}{\sqrt {3}}\right )}{\sqrt {3} b^3 d}+\frac {\left (a+b x^3\right )^{2/3} \left (-5 a^2-2 a b x^3-b^2 x^6\right )}{8 b^3 d} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(x^8*(a + b*x^3)^(2/3))/(a*d - b*d*x^3),x]

[Out]

((a + b*x^3)^(2/3)*(-5*a^2 - 2*a*b*x^3 - b^2*x^6))/(8*b^3*d) - (2^(2/3)*a^(8/3)*ArcTan[1/Sqrt[3] + (2^(2/3)*(a
+ b*x^3)^(1/3))/(Sqrt[3]*a^(1/3))])/(Sqrt[3]*b^3*d) - (2^(2/3)*a^(8/3)*Log[-2*a^(1/3) + 2^(2/3)*(a + b*x^3)^(
1/3)])/(3*b^3*d) + (a^(8/3)*Log[2*a^(2/3) + 2^(2/3)*a^(1/3)*(a + b*x^3)^(1/3) + 2^(1/3)*(a + b*x^3)^(2/3)])/(3
*2^(1/3)*b^3*d)

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fricas [A]  time = 0.72, size = 197, normalized size = 1.11 \begin {gather*} -\frac {8 \cdot 4^{\frac {1}{3}} \sqrt {3} \left (-a^{2}\right )^{\frac {1}{3}} a^{2} \arctan \left (\frac {4^{\frac {1}{3}} \sqrt {3} {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-a^{2}\right )^{\frac {1}{3}} - \sqrt {3} a}{3 \, a}\right ) + 4 \cdot 4^{\frac {1}{3}} \left (-a^{2}\right )^{\frac {1}{3}} a^{2} \log \left (4^{\frac {2}{3}} {\left (b x^{3} + a\right )}^{\frac {1}{3}} \left (-a^{2}\right )^{\frac {2}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} a - 2 \cdot 4^{\frac {1}{3}} \left (-a^{2}\right )^{\frac {1}{3}} a\right ) - 8 \cdot 4^{\frac {1}{3}} \left (-a^{2}\right )^{\frac {1}{3}} a^{2} \log \left (-4^{\frac {2}{3}} \left (-a^{2}\right )^{\frac {2}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}} a\right ) + 3 \, {\left (b^{2} x^{6} + 2 \, a b x^{3} + 5 \, a^{2}\right )} {\left (b x^{3} + a\right )}^{\frac {2}{3}}}{24 \, b^{3} d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^8*(b*x^3+a)^(2/3)/(-b*d*x^3+a*d),x, algorithm="fricas")

[Out]

-1/24*(8*4^(1/3)*sqrt(3)*(-a^2)^(1/3)*a^2*arctan(1/3*(4^(1/3)*sqrt(3)*(b*x^3 + a)^(1/3)*(-a^2)^(1/3) - sqrt(3)
*a)/a) + 4*4^(1/3)*(-a^2)^(1/3)*a^2*log(4^(2/3)*(b*x^3 + a)^(1/3)*(-a^2)^(2/3) + 2*(b*x^3 + a)^(2/3)*a - 2*4^(
1/3)*(-a^2)^(1/3)*a) - 8*4^(1/3)*(-a^2)^(1/3)*a^2*log(-4^(2/3)*(-a^2)^(2/3) + 2*(b*x^3 + a)^(1/3)*a) + 3*(b^2*
x^6 + 2*a*b*x^3 + 5*a^2)*(b*x^3 + a)^(2/3))/(b^3*d)

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: NotImplementedError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^8*(b*x^3+a)^(2/3)/(-b*d*x^3+a*d),x, algorithm="giac")

[Out]

Exception raised: NotImplementedError >> Unable to parse Giac output: Algebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensio
ns not allowed in a rootofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a ro
otofAlgebraic extensions not allowed in a rootofAlgebraic extensions not allowed in a rootofa^2*((2*a)^(1/3))^
2*1/6/b^3/d*ln(((a+b*x^3)^(1/3))^2+(2*a)^(1/3)*(a+b*x^3)^(1/3)+(2*a)^(1/3)*(2*a)^(1/3))-a^2*((2*a)^(1/3))^2/sq
rt(3)/b^3/d*atan(((a+b*x^3)^(1/3)+1/2*(2*a)^(1/3))/sqrt(3)*2/(2*a)^(1/3))-2*(2*a)^(1/3)*a^3*b^24*d^8*(2*a)^(1/
3)*1/6/a/b^27/d^9*ln(abs((a+b*x^3)^(1/3)-(2*a)^(1/3)))-(1/8*((a+b*x^3)^(1/3))^2*(a+b*x^3)^2*b^21*d^7+1/2*((a+b
*x^3)^(1/3))^2*a^2*b^21*d^7)/b^24/d^8

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maple [F]  time = 0.58, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (b \,x^{3}+a \right )^{\frac {2}{3}} x^{8}}{-b d \,x^{3}+a d}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^8*(b*x^3+a)^(2/3)/(-b*d*x^3+a*d),x)

[Out]

int(x^8*(b*x^3+a)^(2/3)/(-b*d*x^3+a*d),x)

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maxima [A]  time = 1.17, size = 155, normalized size = 0.88 \begin {gather*} -\frac {\frac {8 \, \sqrt {3} 2^{\frac {2}{3}} a^{\frac {8}{3}} \arctan \left (\frac {\sqrt {3} 2^{\frac {2}{3}} {\left (2^{\frac {1}{3}} a^{\frac {1}{3}} + 2 \, {\left (b x^{3} + a\right )}^{\frac {1}{3}}\right )}}{6 \, a^{\frac {1}{3}}}\right )}{d} - \frac {4 \cdot 2^{\frac {2}{3}} a^{\frac {8}{3}} \log \left (2^{\frac {2}{3}} a^{\frac {2}{3}} + 2^{\frac {1}{3}} {\left (b x^{3} + a\right )}^{\frac {1}{3}} a^{\frac {1}{3}} + {\left (b x^{3} + a\right )}^{\frac {2}{3}}\right )}{d} + \frac {8 \cdot 2^{\frac {2}{3}} a^{\frac {8}{3}} \log \left (-2^{\frac {1}{3}} a^{\frac {1}{3}} + {\left (b x^{3} + a\right )}^{\frac {1}{3}}\right )}{d} + \frac {3 \, {\left ({\left (b x^{3} + a\right )}^{\frac {8}{3}} + 4 \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} a^{2}\right )}}{d}}{24 \, b^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^8*(b*x^3+a)^(2/3)/(-b*d*x^3+a*d),x, algorithm="maxima")

[Out]

-1/24*(8*sqrt(3)*2^(2/3)*a^(8/3)*arctan(1/6*sqrt(3)*2^(2/3)*(2^(1/3)*a^(1/3) + 2*(b*x^3 + a)^(1/3))/a^(1/3))/d
- 4*2^(2/3)*a^(8/3)*log(2^(2/3)*a^(2/3) + 2^(1/3)*(b*x^3 + a)^(1/3)*a^(1/3) + (b*x^3 + a)^(2/3))/d + 8*2^(2/3
)*a^(8/3)*log(-2^(1/3)*a^(1/3) + (b*x^3 + a)^(1/3))/d + 3*((b*x^3 + a)^(8/3) + 4*(b*x^3 + a)^(2/3)*a^2)/d)/b^3

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mupad [B]  time = 4.91, size = 206, normalized size = 1.16 \begin {gather*} -\frac {{\left (b\,x^3+a\right )}^{8/3}}{8\,b^3\,d}-\frac {a^2\,{\left (b\,x^3+a\right )}^{2/3}}{2\,b^3\,d}-\frac {4^{1/3}\,a^{8/3}\,\ln \left ({\left (b\,x^3+a\right )}^{1/3}-2^{1/3}\,a^{1/3}\right )}{3\,b^3\,d}-\frac {4^{1/3}\,a^{8/3}\,\ln \left (\frac {4\,a^6\,{\left (b\,x^3+a\right )}^{1/3}}{b^6\,d^2}-\frac {2\,4^{2/3}\,a^{19/3}\,{\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}^2}{b^6\,d^2}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{3\,b^3\,d}+\frac {4^{1/3}\,a^{8/3}\,\ln \left (\frac {4\,a^6\,{\left (b\,x^3+a\right )}^{1/3}}{b^6\,d^2}-\frac {18\,4^{2/3}\,a^{19/3}\,{\left (\frac {1}{6}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )}^2}{b^6\,d^2}\right )\,\left (\frac {1}{6}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )}{b^3\,d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^8*(a + b*x^3)^(2/3))/(a*d - b*d*x^3),x)

[Out]

(4^(1/3)*a^(8/3)*log((4*a^6*(a + b*x^3)^(1/3))/(b^6*d^2) - (18*4^(2/3)*a^(19/3)*((3^(1/2)*1i)/6 + 1/6)^2)/(b^6
*d^2))*((3^(1/2)*1i)/6 + 1/6))/(b^3*d) - (a^2*(a + b*x^3)^(2/3))/(2*b^3*d) - (4^(1/3)*a^(8/3)*log((a + b*x^3)^
(1/3) - 2^(1/3)*a^(1/3)))/(3*b^3*d) - (4^(1/3)*a^(8/3)*log((4*a^6*(a + b*x^3)^(1/3))/(b^6*d^2) - (2*4^(2/3)*a^
(19/3)*((3^(1/2)*1i)/2 - 1/2)^2)/(b^6*d^2))*((3^(1/2)*1i)/2 - 1/2))/(3*b^3*d) - (a + b*x^3)^(8/3)/(8*b^3*d)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \frac {\int \frac {x^{8} \left (a + b x^{3}\right )^{\frac {2}{3}}}{- a + b x^{3}}\, dx}{d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**8*(b*x**3+a)**(2/3)/(-b*d*x**3+a*d),x)

[Out]

-Integral(x**8*(a + b*x**3)**(2/3)/(-a + b*x**3), x)/d

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